Auto Up Skill Sro Online

Run daily at 02:00 :

# Formula raw_update = ( 0.4 * recent_avg + 0.3 * task_success_rate * 100 + 0.2 * peer_percentile + 0.1 * self.current_score ) * decay_factor

Below is a structured feature design, including backend logic, API, database changes, and a simple UI concept. Objective Automatically adjust a user’s skill score/level based on recent performance, task completion, peer comparison, and time decay — without manual intervention. 1. Core Logic (Python-like pseudocode) class AutoUpSkillSRO: def __init__(self, user_id, skill_id): self.user_id = user_id self.skill_id = skill_id self.current_score = self.get_current_sro_score() self.performance_history = self.get_recent_assessments(days=30) def compute_new_score(self): # Factors recent_avg = self.average_last_n_scores(5) task_success_rate = self.get_task_success_rate() peer_percentile = self.get_peer_percentile() decay_factor = self.apply_time_decay() auto up skill sro

def apply_time_decay(self): days_since_last_activity = self.get_inactivity_days() if days_since_last_activity > 14: return max(0.7, 1 - (days_since_last_activity - 14) * 0.01) return 1.0

I'll help you develop a feature for (likely a Skill Rating/Optimization system, or an auto-upgrading mechanism for a Skill Ranking Object in a game or LMS). Run daily at 02:00 : # Formula raw_update = ( 0

return ( <div className="skill-card"> <h3>Skill Rating (Auto SRO)</h3> <div className="score">currentScore / 100</div> <label> <input type="checkbox" checked=autoEnabled onChange=(e) => setAutoEnabled(e.target.checked) /> Enable auto up-skilling </label> <button onClick=triggerManualUpgrade>Force Recalculate</button> <small>Auto-updates daily based on recent performance & peer comparison.</small> </div> );

"status": "success", "previous_score": 74.2, "new_score": 78.5, "delta": +4.3, "factors": "recent_performance": 82.0, "task_success_rate": 88.5, "peer_percentile": 65.0, "decay_applied": 0.98 14: return max(0.7

new_score = min(100, max(0, raw_update)) # clamp 0–100 return round(new_score, 1)