Calcolo | Combinatorio E Probabilita -italian Edi...

Choose 1 from town A: 5 ways, 1 from B: 5, 1 from C: 5, 1 from D: 5, but we need exactly 3 towns — so first choose which 3 towns out of 4: (\binom{4}{3} = 4) ways. For each set of 3 towns: choose 1 person from each: (5 \times 5 \times 5 = 125) combinations. Then arrange them in order: (3! = 6) ways. Total favorable ordered selections: [ 4 \times 125 \times 6 = 3000 ]

The beekeeper picked honey (not on the menu), the nun picked mushrooms, the clown picked pineapple (scandalous). All different.

[ \frac{720}{1000} = 0.72 \quad (72%) ]

[ P(\text{pizza}) = \frac{9}{10} ]

Enzo clapped. "A combinatorial probability with two stages!" Calcolo combinatorio e probabilita -Italian Edi...

Thus, overall probability that a pizza is made the customers are from three different towns: [ \frac{9}{10} \times \frac{25}{57} = \frac{225}{570} = \frac{45}{114} = \frac{15}{38} \approx 0.3947 ] The Revelation Chiara finished her wine. "Enzo, your pizza game is a lesson in combinatorics and probability."

Enzo laughed. "Life is random, cara mia . But understanding the combinations helps you not fear the uncertainty." Choose 1 from town A: 5 ways, 1

"So most of the time," Marco laughed, "the pizza is a mix of three distinct flavors!" That night, a boy named Luca asked the most curious question: "What if you drew the names without replacement from a total of 20 customers, but then the three chosen still pick toppings with repetition? And also, before picking toppings, you shuffle a deck of 40 Scoppia cards (Italian regional cards: four suits, numbered 1 to 10). If the first card is a '1' of any suit, you cancel the pizza game. If not, you proceed. What’s the chance we actually make a pizza?"