Vector Mechanics Dynamics 9th Edition Beer Johnston Solution 1 Page

The magnitude of the resultant force $R$ is $242.11 \text{ N}$.

To find the resultant force $R$, resolve the forces $F_1$ and $F_2$ into their x and y components. The magnitude of the resultant force $R$ is $242

The x-component of the resultant force $R$ is: $R_x = F_{1x} + F_{2x} = 86.60 + 75 = 161.60 \text{ N}$ The y-component of the resultant force $R$ is:

The y-component of $F_1$ is: $F_{1y} = F_1 \sin 30^\circ = 100 \sin 30^\circ = 50 \text{ N}$ The magnitude of the resultant force $R$ is $242

The preceding example displays one method of supporting students as they build foundational knowledge with "Vector Mechanics for Engineers: Dynamics 9th Edition Beer Johnston Solution 1" .

The y-component of the resultant force $R$ is: $R_y = F_{1y} + F_{2y} = 50 + 129.90 = 179.90 \text{ N}$

The x-component of $F_1$ is: $F_{1x} = F_1 \cos 30^\circ = 100 \cos 30^\circ = 86.60 \text{ N}$